The work done by a force `vecF` during a displacement `vecr` is given by `vecF.vecr`. Suppose a force of 12 N acts on a particle in vertically upward directionand the particle is displaced through 2.0 m in vertically downward direction. Find the work done by the force during this displacement.

Answer

B, D

Explanation

The angle between the force F and the displacement
r is `180^(@)`. Thus, the work done is
` W = F.r`
`=Fr cos theta`
`= (12 N)(2.0m)(cos 180^@)`
`=- 24 N-m =- 24 J`.