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Accleration-time graph of a particle mov...

Accleration-time graph of a particle moving in a straight line is as shown in Fig. Velocity of particle at time `t=0` is `2 m//s.` Find the velocity at the end of fourth second.

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The correct Answer is:
A
`int dv=inta dt`
or change in velocity=area under a-t graph
Hence, `v_f-v_i=1/2(4)(4)`
`=8 m//s`
`:. v_f=v_i+8=(2+8) m//s`
`= 10 m//s`
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