Home
Class 11
PHYSICS
A particle starts with an initial veloci...

A particle starts with an initial velocity and passes successively over the two halves of a given distance with constant accelerations `a_1 and a_2` respectively. Show that the final velocity is the same as if the whole distance is covered with a uniform acceleration `(a_1 + a_2)/2 .`

Text Solution

Verified by Experts

The correct Answer is:
A



In the first case,
`v_1^2=u^2 + 2a_1 s …(i)`
`v_2^2=v_1^2 + 2a_2 s …(ii)`
Adding Eqs. (i) and (ii), we have
`v_2^2 = u^2 + 2 ((a_1 + a_2)/2) (2s) …(iii)`
In the second case,
`v^2 = u^2 + 2 ((a_1 + a_2)/2) (2s) …(iv)`
From Eqs. (iii) and (iv), we can see that
`v_2=v` Hence Proved.
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.1|2 Videos
  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.2|3 Videos
  • KINEMATICS

    DC PANDEY|Exercise Example Type 7|1 Videos
  • GRAVITATION

    DC PANDEY|Exercise (C) Chapter Exercises|45 Videos
  • KINEMATICS 1

    DC PANDEY|Exercise INTEGER_TYPE|15 Videos

Similar Questions

Explore conceptually related problems

Starting from rest a particle is first accelerated for time t_1 with constant acceleration a_1 and then stops in time t_2 with constant retardation a_2. Let v_1 be the average velocity in this case and s_1 the total displacement. In the second case it is accelerating for the same time t_1 with constant acceleration 2a_1 and come to rest with constant retardation a_2 in time t_3. If v_2 is the average velocity in this case and s_2 the total displacement, then

In direct proportion a_1/b_1 = a_2/b_2

A body starts from rest & moves with constant acceleration a_1 for time t_1 then it retards uniformly with a_2 , in time t_2 and finally comes at rest. Find (t_1)/(t_2)

A and B participate in a race with acceleration a_1 and a_2 , respectively . A reaches t times earlier than B at finish line and their velocities at finish line are v_1 and v_2 , respectively. If difference between their velocities is v , then find the value of v

A body A starts from rest with an acceleration a_1 . After 2 seconds, another body B starts from rest with an acceleration a_2 . If they travel equal distances in the 5th second, after the start of A , then the ratio a_1 : a_2 is equal to :

In the figure, blocks A, B and C of mass m each have acceleration a1, a2 and a3 respectively. F_(1) and F_(2) are external forces of magnitudes 2mg and mg respectively, then :

In a car race, car A takes a time t less than car B at the finish and passes the finishing point with speed v more than that of the car B. Assuming that both the cars start from rest and travel with constant acceleration a_1 and a_2 respectively. Show that v=sqrt (a_1 a_2) t.

In a car race, car A takes t_0 time less to finish than car B and passes the finishing point with a velocity v_0 more than car B . The cars start from rest and travel with constant accelerations a_1 and a_2 . Then the ratio (v_0)/(t_0) is equal to.

A body A starts from rest with an acceleration a_1 . After 2 seconds, another body B starts from rest with an acceleration a_2 . If they travel equal distances in the 5^(th) second, after the start of A , then the ratio a_1 : a_2 is equal to :

A particle moves along x axis in such a way that its coordinate x varies with time t according to the equation x = A_0 - A_1 t + A_2 t^2 . The initial velocity of the particle is.