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The horizontal and vertical displacement...

The horizontal and vertical displacements of a particle moving along a curved line are given by `x=5t and y = 2t^2 + t.` Time after which its velocity vector makes an angle of `45^@` with the horizontal is

A

`0.5 s`

B

`1 s`

C

`2 s`

D

`1.5 s`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_x=(dx)/(dt)=5`
`v_y=(dy)/(dt)`
`=(4t+1)`
At `45^@, v_x=v_y`
`rArr t=1s`
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