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A body starts moving with a velocity v0 ...

A body starts moving with a velocity `v_0 = 10 ms^-1.` It experiences a retardation equal to `0.2v^2.` Its velocity after 2s is given by

A

`+2 ms^-1`

B

`+4 ms^-1`

C

`-2 ms^-1`

D

`+ 6 ms^-1`

Text Solution

Verified by Experts

The correct Answer is:
A
`a=(dv)/(dt)=0.2v^2`
`:. int_10^v -5v^-2=int_0^2dt`
`:. [5/v]_10^v=2`
`:. 5/v-5/10=2`
or `v=2.0 m//s`
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