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Two trains are moving with velocities v1...

Two trains are moving with velocities `v_1 = 10 ms^-1 and v_2 = 20 ms^-1` on the same track in opposite directions. After the application of brakes if their retarding rates are `a_1 = 2 ms^-2 and a_2 = 1 ms^-2` respectively, then the minimum distance of separation between the trains to avoid collision is

A

150 m

B

225 m

C

450 m

D

300 m

Text Solution

Verified by Experts

The correct Answer is:
B
`d=d_1+d_2`
`=(v_1^2)/(2a_1)+(v_2^2)/(2a_2)`
`((10)^2)/(2xx2)+((20)^2)/(2xx1)`
`=225m`
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