A farmer has to go 500 m due north, 400 m due east and 200 m due south to reach his field. If he takes 20 min to reach the field.
(a) What distance he has to walk to reach the field ?
(b) What is the displacement from his house to the field ?
(c) What is the average speed of farmer during the walk ?
(d) What is the average velocity of farmer during the walk ?

Answer

A, B, C, D

Explanation

(a) `Distance=AB+BC+CD`
`=(500+400+200)=1100m`
(b) `Displacement=AD=sqrt((AB-CD)^2+BC^2)`
`=sqrt((500-200)^2+(400)^2)`
` = 500m`
(c) Average speed=`("Total distance")/("Total time")`
`=1100/20=55m//`min
(d) Average velocity=`(AD)/t`
`= 500/20=25m//min (along AD)`