Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take `g = 10 m//s^2.`

Answer

A

Explanation

Given `h_1-h_2=10m`

`:. 1/2g t^2-1/2g(t-1)^2=10`
Solving equation, we get `t=1.5s`