Two bodies are projected vertically upwards from one point with the same initial velocity `v_0.` The second body is projected `t_0 s` after the first. How long after will the bodies meet?

Answer

B

Explanation

At the time of collision,
`s_1=s_2`
`:. v_0t-1/2g t^2=v_0(t-t_0)-1/2g(t-t_0)^2`
Solving this equation we get,
`t=(v_0)/g+(t_0)/2`