A point mass starts moving in a straight line with constant acceleration. After time `t_0` the acceleration changes its sign, remaining the same in magnitude. Determine the time T from the beginning of motion in which the point mass returns to the initial position.

Answer

A, C, D

Explanation

If we start time calculation from point P and apply
the equation

`s=ut+1/2at^2`
`(-1/2at_0^2)=(+at_0)t+1/2(-a)t^2`
Solving we get, `t=(sqrt2+1)t_0`
`=2.414 t_0`
`:.` Total time, `T=t+t_0`
`=(3.414)t_0`