A car moving with constant acceleration covered the distance between two points `60.0 m` apart in `6.00 s.` Its speed as it passes the second point was `15.0 m//s.`
(a) What is the speed at the first point?
(b) What is the acceleration?
(c) At what prior distance from the first was the car at rest?

Answer

A, B, C

Explanation

(a) and (b) `60=u(6)+1/2xxaxx(6)^2`
`15=u+(a)(6)`
Solving these two equations,we get
`u=5 m//s`
and `a=5/3m//s^2`
(C) `(5)^2=(2)(5/3)s (v^2=2as)`
`:. s=7.5m`