Figure shows the acceleration-time graph of a particle moving along a straight line. After what time the particle acquires its initial velocity?

Answer

B, C

Explanation

Area of a-t graph gives change in velocity
`:. Deltav=v_f-v_i`=area of a-t graph
Since, `v_f-v_i`

`:.` Net area of a-t graph should be zero
`:.` Area OABC=AreaCDE
Substituting the values we get,
`t_E=(2+sqrt3)s`