A man standing on a hill top projects a stone horizontally with speed `v_0` as shown in figure. Taking the co-ordinate system as given in the figure. Find the co-ordinates of the point where the stone will hit the hill surface.

Answer

A

Explanation

Range of the projectile on an inclined plane (down the
plane) is,

` R=(u^2)/(gcos^2beta)[sin(2alpha+beta)+ sinbeta]`
Here, `u=v_0, alpha=0 and beta = theta`
`:. R=(2v_(0)^2 sin theta)/(g cos^2 theta)`
Now, `x=R cos theta = (2v_(0)^2 tan theta)/(g)`
and `y= -R sin theta = -(2v_(0)^2 tan^2 theta)/(g)` .