" I.Divide "49p^(3)" by "-7sqrt(7)p^(2)

Divide 49p^3 by -7sqrt7 p^2

log_sqrt(7)(49) =

Find the degree of the following polynomials. 2sqrt(5) p^(4) - ( 8p^(3))/( sqrt(3)) + ( 2p^(2))/( 7)

If p=-2, find the value of : (i) 4p+7 (ii) -3p^(2)+4p+7( iii) -2p^(3)-3p^(2)+4p+7

Let P(n) be the statement "7 divides 2^(3n)-1 ." What is P(n+1) ?

Factorise 49p^2 – 36

Factorise : 49p^(2)-36

Divide p(x)= 3x^2 +x +7 by x+2 .

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then the value of p is (7)/(2sqrt(3))( b) (7)/(3)( c) (3sqrt(7))/(2)( d) (7)/(3sqrt(2))