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The range of a projectile at an angle th...

The range of a projectile at an angle `theta` is equal to half of the maximum range if thrown at the same speed. The angel of projection `theta` is given by

A

`15^@`

B

`30^@`

C

`60^@`

D

data insufficient

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(theta) = R_(45^@)/2`
`:. (u^2sin2theta)/g = 1/2 ((u^2)/g) or sin 2 theta = 1/2`
`:. 2theta = 30^@ or theta = 15^@` .
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DC PANDEY-PROJECTILE MOTION-Level - 1 Single Correct
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