A body is projected at time `t = 0` from a certain point on a planet's surface with a certain velocity at a certain angle with the planet's surface (assumed horizontal). The horizontal and vertical displacement x and y (in metre) respectively vary with time t in second as, `x= (10sqrt(3)) t and y= 10t - t^2`. The maximum height in meter attained by the body is

Answer

25

Explanation

For maximum value of y
`(dy)/(dt) = 10-2t = 0 `
`rArr t = 5s`
`y_(max) = (10)(5) -(5)^2`
= 25m.