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A fixed mortar fires a bomb at an angle ...

A fixed mortar fires a bomb at an angle of `53^@` above the horizontal with a muzzle velocity of `80 ms^-1`. A tank is advancing directly towards the mortar on level ground at a constant speed of `5m//s`. The initial separation (at the instant mortar is fired) between the mortar and tank, so that the tank would be hit is `[Take g = 10 ms^-2]`

A

662.4m

B

526.3m

C

486.6m

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D

`T = (2usintheta)/g = ((2)(8)sin 53^@)/10 = 1.28s`
`R = (u^2sin2theta)/g = ((80)^2 sin (106^@))/10 = 615.2 m`
Distance travelled by tank,
`d = (5)T = (5)(1.28) = 6.4m`
`:.` Total distance `= (615.2 + 6.4)m`
`=621.6m`.
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DC PANDEY-PROJECTILE MOTION-Level - 1 Single Correct
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  12. Average velocity of a particle in projectile motion between its starti...

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  14. A body is projected at time t = 0 from a certain point on a planet's s...

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