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A particle is projected from the bottom of an inclined plane of inclination `30^@` with velocity of `40 m//s` at an angle of `60^@` with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane. Take `g = 10 m//s^2`.

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Verified by Experts

The correct Answer is:
C, D
Horizontal component of velocity always remains
constant
`:. 40 cos 60^@ = v cos 30^@`
or `v= 40/(sqrt3) m//s`.
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