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A particle is dropped from a height h. A...

A particle is dropped from a height h. Another particle which is initially at a horizontal distance d from the first is simultaneously projected with a horizontal velocity u and the two particles just collide on the ground. Then

A

`d^2 = (u^2h)/(2h)`

B

`d^2 = (2u^2h)/g`

C

`d=h`

D

`gd^2 = u^2h`

Text Solution

Verified by Experts

The correct Answer is:
B
`T = (sqrt (2h)/g)`
`d = (u)T = u (sqrt(2h)/g)`
`:. d^2 = (2hu^2)/g` .
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Knowledge Check

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