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A projectile is projected with speed u a...

A projectile is projected with speed u at an angle of `60^@` with horizontal from the foot of an inclined plane. If the projectile hits the inclined plane horizontally, the range on inclined plane will be.

A

`(u^2(sqrt21))/(2g)`

B

`(3u^2)/(4g)`

C

`u^2/(2beta)`

D

`((sqrt21)u^2)/(8g)`

Text Solution

Verified by Experts

The correct Answer is:
D

`R/2 = (u^2sin 2(60^@))/(2g)`
`= (sqrt(3)u^2)/(4g)`
`H = (u^2sin260^@)/(2g) = (3u^2)/(8g)`
`:. AB = sqrt((R/2)^2 + H^2)`
`=((sqrt(21))u^2)/(8g)`
.
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