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A particle is projected from a point P w...

A particle is projected from a point P with a velocity v at an angle `theta` with horizontal. At a certain point Q it moves at right angles to its initial direction. Then

A

velocity of particle at Q is v `sin theta`

B

velocity of particles at Q is v `cot theta`

C

time of flight from `P to Q` is `(v//g)cosec theta`

D

time of flight from `P to Q` is `(v//g) sec theta`

Text Solution

Verified by Experts

The correct Answer is:
B, C
Horizontal component of velocity remains
unchanged
`:. v cos theta = v' cos (90-theta)`
or `v' = v cot theta`
In vertical (y) direction,
`v_(y) = u_(y) + a_(y)t`
`:. t = (v_y-u_y)/a_y`
`= (-v^1sin(90-theta) -vsintheta)/(-g)`
`= ((vcot theta)* cos theta + v sin theta)/(g)`
`=(v cosec theta)/g` .
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