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Two inclined planes OA and OB intersect ...

Two inclined planes OA and OB intersect in a horizontal plane having their inclinations `alpha and beta` with the horizontal as shown in figure. A particle is projected from P with velocity u along a direction perpendicular to plane OA. The particle strikes plane OB perpendicularly at Q.

If `alpha = 30^@ , beta = 30^@` the time of flight from P to Q is

A

`u/g`

B

`((sqrt3)u)/g`

C

`((sqrt2)u)/g`

D

`(2u)/g`

Text Solution

Verified by Experts

The correct Answer is:
B
At Q, component parallel to OB becomes zero

`v_x = u_x + a_xt`
`0= (u cos 30^@) + (-g sin 30^@)t`
`:. t = u/g cot 30^@ = ((sqrt3)u)/g`.
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