Figure shown a man standing stationary with respect to a horizontal converyor belt that is accelerationg with `1m//s^(-2)` . What is the net force on the man?If the coefficient of ststic friction between the man's shoes and the belt is `0.2` upto what maximum acceleration of the belt can the man continue to be stationary relative to the belt? Mass of the man`= 65kg (g =9.8m//s^(2))`

Explanation

As the man standing stationary e.r.t. the belt
`:.` acceleration of the man = acceleration of the belt
`= a=1m//s^(-2)`
Mass of the man `m = 65kg`
net force on the man `= ma =65 xx1 =65N`
Give coefficient of friction, `mu =0.2`
`:.` Limiting friction, `f_(L) =mu mg`
If the man reamains stationary with respect to the maximum acceleration `a_(0)` of the belt, then
`ma_(0) =f_(L) =mumg`
`a_(0) =mug = 0.2xx9.8 =1.96m//s^(-2)`