A small marble is projected with a velocity of `10 m//s` in a direction `45^(@)`from the y-direction on the smooth inclined plane. Calculate the magnitude `v` of its velocity of after `2 s` (Take `g = 10 m//s^(2))`

Answer

A

Explanation

It is just like a projectile motion with `g` to be replaced by `g sin 45^(@)`
`After 2 s,`
`nu = sqrt(nu_(x)^(2) + nu_(y)^(2))`
`= sqrt((10 sin 45^(@) - (g)/(sqrt2) xx 2) + (10 cos 45^(@))^(2))`
`= 10 m//s`