A block of mass `m` slides down an inclined right angled trough .If the coefficient of friction between block and the trough is `mu_(k)` acceleration of the block down the plane is

Answer

A, B, C

Explanation

`sqrt2 N = mg cos theta`
`:. N = (mg cos theta)/(sqrt2)`
`a = (mg sin theta - 2 mu_(k) N)/(m)`
`= g sin theta - sqrt2 mu_(k) g cos theta`
`= g (sin theta - sqrt2 mu_(k) cos theta)`