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potential enrgy of a particle along x-ax...

potential enrgy of a particle along x-axis varies as, `U=-20 + (x-2)^(2)`, where U is in joule and x in meter. Find the equilibrium position and state whether it is stable or unstable equilibrium.

A

U=-20

B

x=2

C

U=+20

D

x=-2

Text Solution

Verified by Experts

`U= "minimum" =-20J`
at `x=2m`
`:. x=2m` is stable equilibrium position.
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