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Asseration : Displacement time graph of ...

Asseration : Displacement time graph of a particle moving in a straight line is shown in figure. Work done by all the forces between time interval `t_(1)` and `t_(2)` is definitely zero.
,
Reason : Work done by all the forces is equal to change in kinetic energy.

A

If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

B

If both Assertion and Reason are true and the Reason is not the correct explanation of the Assertion.

C

If Assertion is true, but the Reason is false

D

If Assertion is false but the Reason is true.

Text Solution

Verified by Experts

The correct Answer is:
D

`W_(All) =DeltaK =K_(f)-K_(i)`
`=1/2m(v_(f)^(2)-v_(i)^(2))`
`v_(f) =v_(t_2) =`Slope of `s-t` graph at `t_(2)`
`v_(i) =v_(t_1)=slope of st graph at t_(1)`
these two slopes are not necessarily equal.
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Knowledge Check

  • Displacement time graph of a particle moving in a straight line is a shown in figure.

    A
    in region `A` acceleration is positive
    B
    in region `B` acceleration is negative
    C
    in region `C` acceleration is positive
    D
    in region `D` acceleration is negative
  • The total work done on a particle is equal to the change in its kinetic energy

    A
    always
    B
    only if the forces acting on ilt are conservative
    C
    only if gravitational force alone acts on it
    D
    only if elastic force alone acts on it
  • Displacement time graph of a particle moving in a straight line is as shown in figure. From the graph we can conclude that work done on the block is : .

    A
    positive from `0` to `t_(1)`
    B
    negative from `t_(1)` to `t_(2)`
    C
    zero from `t_(2)` to `t_(3)`
    D
    negative from `t_(3)` to `t_(4)`.
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