A body has kinetic energy E when projected at angle of projection for maximum range. Its kinetic energy at the highest point of its path will be

Options

A. `E`
B. `(E)/(2)`
C. `(E)/(sqrt(2))`
D. `zero`

Answer

B

Explanation

Maximum range is obtained at `45^(@)`.
`:. E' =1/2mv^(2) =1/2m ((u)/(sqrt2))^(2)`
`=(((1)/(2)m u^(2)))/2 =E/2`.