Two springs have force constants `k_(A)` and `k_(B)` such that `k_(B)=2k_(A)`. The four ends of the springs are stretched by the same force. If energy stored in spring `A` is `E`, then energy stored in spring `B` is.

Options

A. `E/2`
B. `2E`
C. `E`
D. `4E`

Answer

A

Explanation

`F =Kx rArr x =F/k`
Now, `U=(1)/(2)kx^(2)`
`=1/2k(F/k)^(2)`
or `Uprop1/2`
`k_(B)` is double. Therefore, `U_(B)` will be half.