A body of mass 100 g is attached to a hanging spring force constant is `10 N//m`. The body is lifted until the spring is in its unstretched state and then released. Calculate the speed of the body when it strikes the table `15 cm` release point .

Options

A. `1 m//s`
B. `0.866 m//s`
C. `0.225 m//s`
D. `1.5 m//s`

Answer

B

Explanation

`E_(i) =E_(f)`
`0=1/2 xx 10 xx (0.15)^(2) -0.1 xx 10 xx 0.15`
`+ 1/2 xx 0.1 xx v^(2)`
`:. v=0.866 m//s`.