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Two equal masses are attached to the two...

Two equal masses are attached to the two end of a spring of force constant `k` the masses are pulled out symmetrically to stretch the spring by a length `2x_(0)` over its natural length. Find the work done by the spring on each mass.

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The correct Answer is:
B
Total work done `=-(1)/(2)K(2x_(0))^(2) =-2 Kx_(0)^(2)`
`:.` work done on one mass
`(-2Kx_(0)^(2))/2 =-K_x^(2)`.
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