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A rod of length 1.0 m and mass 0.5 kg fi...

A rod of length `1.0 m` and mass `0.5 kg` fixed at ond is initially hanging vertical. The other end is now raised until it makes an angle `60^@` with the vertical. How much work is required?

Text Solution

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The correct Answer is:
A, B
For increase in gravitational potential energy of a rod we see the centre of the rod.
.
`W =` change in potential energy
`=mgl/2(1-cos theta)`
Substituting the values, we have
` W =(0.5) (9.8)((1.0)/(2))(1-cos60^(@))`
`=1.225 J`.
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