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A car of mass m is accelerating on a lev...

A car of mass m is accelerating on a level smooth road under the action of a single F. The power delivered to the car is constant and equal to P. If the velocity of the car at an instant is v, then after travelling how much distance it becomes double?
.

A

(a) `(7mv^(3))/(3P)`

B

(b) `(4mv^(3))/(3P)`

C

(c) `(mv^(3))/(P)`

D

(d) `(18mv^(3))/(7P)`

Text Solution

Verified by Experts

The correct Answer is:
A
`P=Fv ="constant"`
`:. F =P/v`
`:. mv((dv)/(ds))=P/v`
`:. Int_(0)^(s)ds =(m)/(P)int_(v)^(2v)v^(2)dv`
solving we get, `s=(7mv^(3))/(3P)`.
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