A block tied between identical springs is in equilirium. If upper spring is cut, then the acceleration of the nlock just after cut is `5 ms^(1)` Now if instead of upper string lower spring is cut, then the acceleration of the block just after the cut will be (Take `g=10 m//s^(2)`).

Options

A. `1.25 ms^(-2)`
B. `5 ms^(-2)`
C. `10 ms^(-2)`
D. `2.5 ms^(-2)`

Answer

B

Explanation

In both cases sudden changes in force by cutting the spring would be kx.
`:. a = (DeltaF)/m =(kx)/m` (in both case )
In one case it is downwards and other case it is upwards.