A particle moves in a particle of radius `0.5 m` at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from `2.0m//s` to `4.0 m//s` in `4.0s`

Options

A. `1 rad//s^(2)`
B. `2 rad//s^(2)`
C. `3 rad//s^(2)`
D. None of the above

Answer

A

Explanation

The tangential acceleration of the particle is
`a_(t)=(dv)/(dt) =(4.0-2.0)/4.0=0.5 m//s^(2)`
The angular acceleration is `alpha=(a_(t))/r=0.5/0.5=1 rad//s^(2)`