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A particle moves in a circle of radius ...

A particle moves in a circle of radius `1.0cm` with a speed given by `v=2t` , where `v` is in `cm//s` and `t` in seconds.
(a) Find the radial accerleration of the particle at `t=1s` .
(b) Find the tangential accerleration of the particle at `t=1s` .
Find the magnitude of net accerleration of the particle at `t=1s` .

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
(a) `a_(r)=(v^(2))/(R)=((2t)^(2))/(1.0)=4t^(2)`
At n`t=1s,a_(r)=4cm//s^(2)`
(b) `a_(t)=(dv)/(dt)=2cm//s^(2)`
(c) `a=sqrt(a_(r)^(2)+a_(r)^(2))=sqrt((4)^(2)+(2)^(2))`
`=2sqrt(5)cm//s^(2)`
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