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A simple pendulum of length l and bob of...

A simple pendulum of length `l` and bob of mass `m` is displaced from its equilibrium position `O` to a position `P` so that height of `P` above `O` is `h` . If is then released. What is the tension in the string when the bob passes through the through the equilibrium position `O` ? Neglect friction. `v` is the velocity of the bob at `O`

A

`m(g+(v^(2))/(l))`

B

`(2mgh)/(l)`

C

`mg(1+(h)/(l))`

D

`mg(1+(2h)/(l))`

Text Solution

Verified by Experts

The correct Answer is:
D
`v^(2)=2gh`

`T-mg=(mv^(2))/(l)`
or `T=mg+(m(2gh))/(l)`
`=mg(1+(2h)/(l))`
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