A `70kg` man stands in contact against the inner wall of a hollw cylindrical drum of radius `3m` rotating about its verticle axis. The coefficient of friction between the wall and his clothing nis `0.15` . What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed?

Answer

A, D

Explanation

`N=mRomega^(2)`
`muN=mg`
From these two equations we get,
`omega=sqrt((g)/(muR)`
`=sqrt((9.8)/(0.15xx3))=4.7rad//s`