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A particle is projected with a speed u a...

A particle is projected with a speed u at angle `theta` with the horizontal. Consider a small part of its path near the highest position and take it approximately to be a circular arc. What is the radius of this circle? This radius is called the adius of curvature of the curve at the point.

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The correct Answer is:
A, B, C
`a=(v^(2))/(R) implies R=(v^(2))/(a)=((ucostheta)^(2))/(g)`
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