A boy whirls a stone of small mass in a horizontal circle of radius `1.5m` and at height `2.9m` above level ground. The string breaks and the stone flies off horizontally and strikes the ground after travelling a horizontal distance of `10m` . What is the magnitude of the centripetal acceleration of the stone while in circular motion ?

Answer

A, B, C

Explanation

`t=((2h)/(g))=sqrt((2xx2.9)/(9.8))=0.77s`
Horizontal distance `x=vt`
:. `v=(x)/(t)=(10)/(0.77)`
`~~13m//s`
`a=(v^(2))/(R)=(13^(2))/(1.5)`
`~~113m//s^(2)`