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The bob of the pendulum shown in figure ...

The bob of the pendulum shown in figure describes an are of in a vertical plane. If the tension in the cord is `2.5` times the weight of the bob for the position shown. Find the velocity and the acceleration of the bob in that position.

Text Solution

Verified by Experts

The correct Answer is:
A, B
`2.5mg-mgcos30^(@)=(mv^(2))/(r)`
:. `11.63g=(v^(2))/(r)=(v^(2))/(2)`
`v=5.66m//s`
`F_(n et)=sqrt((2.5mg)^(2)+(mg)^(2)+(2)(2.5mg)(mg)cos150^(@))`
`=1.7mg`
`a_(n et)=(F_(n et))/(m)=1.7g~~16.75m//s^(2)`
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