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A rough horizontal plate rotates with an...

A rough horizontal plate rotates with angular velocity `omega` about a fixed verticle axis. A particle or mass `m` lies on the plate at a distance `(5a)/(4)` from this axis. The coefficient of friction between the plate and the particle is `(1)/(3)` . The largest value of `omega^(2)` for which the oparticle will continue to be at rest on the revolving plate is

A

`(g)/(3a)`

B

`(4g)/(5a)`

C

`(4g)/(9a)`

D

`(4g)/(15a)`

Text Solution

Verified by Experts

The correct Answer is:
D
`mumg=nRomega^(2)`
:. `omega^(2)=(mug)/(R)=((1//3)g)/(5a//4)=(4g)/(15a)`
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