An insect of mass `m=3kg` is inside a vertical drum of radius `2m` that is rotating with an angular velocity of `5rads^(-1)` . The insect doesn't fall off. Then, the minimum coefficient of friction required is

Options

A. `0.5`
B. `0.4`
C. `0.2`
D. None of these

Answer

C

Explanation

`N=mRomega^(2)`

`muN=mg`
Form these two equations, we get ltbr. `mu=(g)/(Romega^(2))`
`=(10)/(2xx(5)^(2))=0.2`