A ball of mass m hits a floor with a speed `v_0` making an angle of incidence `alpha` with the normal. The coefficient of restitution is `e`. Find the speed of the reflected ball and the angle of reflection of the ball.

Answer

A, B

Explanation

The component of velocity `v_0` along common tangent direction `v_0 sin alpha` will remain unchanged. Let v be the component along common normal direction after collision. Applying

Relative speed of separation =e(relative speed of approach)
along common normal direction, we get
`v=ev_0cos alpha`
Thus, after collision components of velocity `v^'` are `v_0sin alpha` and `ev_0cos alpha`
`:. v^'=sqrt((v_0sinalpha)^3+(ev_0cos alpha)^2)`
and `tan beta=(v_0sin alpha)/(ev_0cos alpha)`
or `tan beta=(tanalpha)/(e)`