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All surfaces shown in figure are smooth....

All surfaces shown in figure are smooth. Wedges of mass 'M' is free to move. Block of mass 'm' is given a horizontal velocity `v_0` as shown. Find the maximum height 'h' attained by 'm' (over the wedges or outside it).

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The correct Answer is:
A
At maximum height vertical component of velocity of 'm' wil be zero. It will have only horizontal component of velocity and this is equal to the horizontal component of 'M' also (think why?). So at the highest point figure is like this:

Applying law of conservation of linear momentum in horizontal direction,
`p_i=p_f`
`implies mv_0=(M+m)v` ...(i)
Now, applying law of conservation of mechanical energy,
`E_i=E_f`
`:. 1/2mv_0^2=1/2(M+m)v^2+mgh` ...(ii)
We have two unknowns v and h.
So, we can find the value of 'h' by solving these two equations. ltbr. Exercise: Solve these two equations to find the value of 'h'.
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