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A pendulum bob of mass 10^-2kg is raised...

A pendulum bob of mass `10^-2kg` is raised to a height `5xx10^-2m` and then released. At the bottom of its swing, it picks up a mass `10^-3kg`. To what height will the combined mass rise?

Text Solution

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The correct Answer is:
A, B, D

Velocity of pendulum bob at bottom most point
`v_1=sqrt(2gh)=sqrt(2xx10xx5xx10^-2)=1m//s`
When the bob picks up a mass `10^-3kg` at the bottom, then by conservation of linear momentum the velocity of combined mass if given by
`m_1v_1+m_2v_2=(m_1+m_2)v`
`10^-2xx1+10^-3xx0=(10^-2+10^-3)v`
or `v=(10^-2)/(1.1xx10^-2)=10/11m//s`
Now, `h=(v^2)/(2g)=((10//11)^2)/(2xx10)=4.1xx10^-2m`
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Knowledge Check

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