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Find the position of centre of mass of t...

Find the position of centre of mass of the section shown in figure

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The correct Answer is:
A
`x_(CM)=(A_1x_1-A_2x_2)/(A_1-A_2)`
`=((4a^2)(a)-(a^2)(3a//2))/(4a^2-a^2)=(5a)/(6)`
`y_(CM)=(A_1y_1-A_2y_2)/(A_1-A_2)`
`=((4a^2)(a)-(a^2)(3a//2))/(4a^2-a^2)`
`=(5a)/(6)`
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