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A straight rod of length L has one of it...

A straight rod of length L has one of its end at the origin and the other at `X=L`. If the mass per unit length of the rod is given by `Ax` where A is constant, where is its centre of mass?

Text Solution

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The correct Answer is:
B, C
`x_(CM)=(int_0^Lxdm)/(int_0^Ldm)=(int_0^L(X)(Axdx))/(int_0^L(Axdx))=2/3L`
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