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A man of mass 60kg jumps from a trolley ...

A man of mass `60kg` jumps from a trolley of mass `20kg` standing on smooth surface with absolute velocity `3m//s`. Find velocity of trolley and total energy produced by man.

Text Solution

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The correct Answer is:
A

`m_1v_1=m_2v_2` (in opposite direction)
`:. (60)(3)=(20)v_2`
`:. v_2=9m//s`
`KE=1/2xx60xx(3)^2+1/2xx20xx(9)^2`
`=1080J=1.08kJ`
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