A machine gun fires a bullet of mass 40 g with a velocity `1200 ms^-1`. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can be fire per second at the most?

Options

A. (a) 3
B. (b) 5
C. (c) 6
D. (d) 9

Answer

A

Explanation

`F=(Deltap)/(Deltat)=n(mv)`
Here n=number of bullets fired per second
`implies n=(F)/(mv)`
`=(144)/((40xx10^-3)(1200))=3`